2016 AMC 10B Real Questions and Analysis
In this article, you’ll find:
- Representative real questions from each module with detailed solutions.
- The complete 2016 AMC 10B Answer Key.
- The best resources to prepare effectively for the AMC 10.
- A concise topic distribution chart showing which areas appeared most in the 2016 AMC 10B.
- A module-to-question mapping table highlighting the core concepts tested in each module for the 2016 AMC 10B.
Real Question and Solutions Explained
Algebra Example – Problem 2
Question:
If \( n \heartsuit m = n^3 m^2 \), what is
\[
\frac{2 \heartsuit 4}{4 \heartsuit 2}?
\]
(A) \( \frac{1}{4} \) (B) \( \frac{1}{2} \) (C) 1 (D) 2 (E) 4
Solution:
Compute each term:
\[
2 \heartsuit 4 = 2^3 \times 4^2 = 8 \times 16 = 128,
\]
\[
4 \heartsuit 2 = 4^3 \times 2^2 = 64 \times 4 = 256.
\]
Hence,
\[
\frac{2 \heartsuit 4}{4 \heartsuit 2} = \frac{128}{256} = \frac{1}{2}.
\]
Answer:(B)
Common Mistakes:
- Mixing exponents (writing \( n^2 m^3 \) instead of \( n^3 m^2 \)).
- Computing \( (2/4)^3 (2/4)^2 \) instead of dividing.
- Forgetting order in the definition of the operation.
Number Theory Example – Problem 8
Question:
What is the tens digit of
\[
2015^{2016} – 2017 \times 2015^{2016 – 2017}?
\]
(A) 0 (B) 1 (C) 3 (D) 5 (E) 8
Solution:
Only the last two digits of \( 2015^{2016} \) matter (mod 100).
Since \( 2015 \equiv 15 \pmod{100} \), find the last two digits of \( 15^{2016} \).
Observe:
\[
15^1 \equiv 15, \quad 15^2 \equiv 25, \quad 15^3 \equiv 75, \quad 15^4 \equiv 25 \pmod{100}.
\]
Thus for \( n \ge 2 \), \( 15^n \equiv 25 \pmod{100}. \)
Hence,
\[
2015^{2016} \equiv 25 \pmod{100}.
\]
Subtracting 2017 gives
\[
25 – 17 = 8 \pmod{100}.
\]
So the tens digit is 0.
Answer:(A)
Common Mistakes:
- Forgetting to reduce modulo 100.
- Assuming repetition every 4 terms without checking the 15 pattern.
- Subtracting 17 incorrectly as mod 10 instead of mod 100.
Geometry Example – Problem 10
Question:
A thin piece of wood in the shape of an equilateral triangle with side length 3 inches weighs 12 ounces. A second, similar triangle has side length 5 inches. What is the weight of the second piece?
(A) 14.0 (B) 16.0 (C) 20.0 (D) 33.3 (E) 55.6
Solution:
For similar figures of uniform thickness and density,
\[
\text{weight} \propto (\text{side length})^2.
\]
Thus,
\[
\frac{W_2}{W_1} = \left( \frac{5}{3} \right)^2 = \frac{25}{9}.
\]
Therefore,
\[
W_2 = 12 \times \frac{25}{9} = 33.\overline{3}.
\]
Answer: (D)
Common Mistakes:
- Scaling by side ratio instead of area ratio.
- Cubing the ratio (confusing with 3D scaling).
- Rounding too early before comparison.
Combinatorics Example – Problem 12
Question:
Two different numbers are selected at random from {1, 2, 3, 4, 5} and multiplied. What is the probability that the product is even?
(A) 0.2 (B) 0.4 (C) 0.5 (D) 0.7 (E) 0.8
Solution:
Total pairs (unordered):
\[
C(5,2) = \frac{5!}{2!\,(5 – 2)!} = 10.
\]
For the product to be odd, both numbers must be odd.
There are 3 odd numbers {1, 3, 5}, so
\[
C(3,2) = \frac{3!}{2!\,(3 – 2)!} = 3.
\]
Hence, even cases = 10 − 3 = 7.
Probability:
\[
P = \frac{7}{10} = 0.7.
\]
Answer:(D)
Common Mistakes:
- Counting ordered pairs instead of combinations.
- Forgetting the phrase “two different numbers.”
- Assuming half are even by symmetry without checking.
2016 AMC 10B Answer Key
| Question | Answer |
|---|---|
| 1 | D |
| 2 | B |
| 3 | D |
| 4 | B |
| 5 | D |
| 6 | B |
| 7 | C |
| 8 | A |
| 9 | C |
| 10 | D |
| 11 | B |
| 12 | D |
| 13 | D |
| 14 | D |
| 15 | C |
| 16 | E |
| 17 | D |
| 18 | E |
| 19 | D |
| 20 | C |
| 21 | B |
| 22 | A |
| 23 | C |
| 24 | D |
| 25 | A |
Download AMC 10 Mock Exam & Practice Pack
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- Mock Exams: Timed practice with full explanations to build test readiness and review mistakes.
- Knowledge Points: Covers must-know Algebra, Geometry, and Number Theory concepts for AMC 10.
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Last 10 Years AMC 10 Real Questions and Analysis
Think Academy provides in-depth breakdowns of the past decade of AMC 10 exams. Click below to explore:
- Year-by-year topic trend insights and concept distributions
- Real AMC 10 exams from the last 10 years
- Official answer keys
- Representative questions, detailed solutions, and common mistakes
2016 AMC 10B Topic Distribution
The 2016 AMC 10B featured 25 questions to be completed in 75 minutes, emphasizing advanced problem-solving and proof-based reasoning skills.
Learn more about AMC 10 Format and Scoring Here: AMC 10 FAQ and Resources: Your Ultimate Guide

Detailed Module Analysis
| Module | Question Numbers | What It Tests (Brief) |
|---|---|---|
| Algebra | 1–5, 7, 8, 10–13, 17, 24 | Equations, ratios, coordinate geometry |
| Number Theory | 14, 20, 23, 25 | Congruence, divisibility |
| Geometry | 6, 15, 19, 21, 22 | Triangles, solids |
| Combinatorics / Probability | 9, 16, 17, 18 | Counting and probability |
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